On 2/6/2022 下午 5:04, Segher Boessenkool wrote:
> Hi!
> 
> On Thu, Jun 02, 2022 at 01:30:04PM +0800, HAO CHEN GUI wrote:
>> Segher,
>>   Does BCD comparison return false when either operand is invalid coding?
> 
> It sets all of LT, GT, and EQ to 0 (it normally sets exactly one of them
> to 1).  It sets bit 3 (the "SO" bit usually) to 1.
> 
> That is what the machine insns do.  What the builtins do is undefined as
> far as I know?  If So we can do whatever is most convenient, so, not
> handle it specifically at all, just go with what falls out.

We defined the following unordered BCD builtins in rs6000-builtin.def.
They check the bit 3 for overflow.

  const signed int __builtin_bcdadd_ov_v1ti (vsq, vsq, const int<1>);
    BCDADD_OV_V1TI bcdadd_unordered_v1ti {}

  const signed int __builtin_bcdadd_ov_v16qi (vsc, vsc, const int<1>);
    BCDADD_OV_V16QI bcdadd_unordered_v16qi {}

Also Xlc defines three BCD builtins for overflow and invalid coding.
https://www.ibm.com/docs/en/xl-c-and-cpp-linux/16.1.1?topic=functions-bcd-test-add-subtract-overflow
Shall GCC keep up with Xlc? Please advise.

Thanks
Gui Haochen

> 
>> If yes, the result could be 3-way. We can check gt and eq bits for ge.
> 
> You can check the LT bit, instead: it is only one branch insn, and also
> only one setbc[r] insn (it can be slightly more expensive if you can use
> only older insns).
> 
>> We still can't use crnot to only check lt bit as there could be invalid
>> coding.
>>   Also, do you think finite-math-only excludes invalid coding? Seems GCC
>> doesn't clear define it.
> 
> This is not floating-point code at all, it should not be influenced at
> all by finite-math-only!
> 
> 
> Segher

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