The following significantly brings down compile-time spent in VRP
for the testcase.

Bootstrapped and tested on x86_64-unknown-linux-gnu, applied to trunk.

Richard.

2019-07-29  Richard Biener  <rguent...@suse.de>

        PR tree-optimization/91257
        * tree-vrp.c (operand_less_p): Avoid dispatching to fold for
        most cases, instead call compare_values which handles the
        symbolic ranges we handle specially.
        (compare_values_warnv): Do not call operand_less_p but open-code
        the effective fold calls.  Avoid converting so much.

Index: gcc/tree-vrp.c
===================================================================
--- gcc/tree-vrp.c      (revision 273792)
+++ gcc/tree-vrp.c      (working copy)
@@ -909,22 +909,17 @@ operand_less_p (tree val, tree val2)
   /* LT is folded faster than GE and others.  Inline the common case.  */
   if (TREE_CODE (val) == INTEGER_CST && TREE_CODE (val2) == INTEGER_CST)
     return tree_int_cst_lt (val, val2);
+  else if (TREE_CODE (val) == SSA_NAME && TREE_CODE (val2) == SSA_NAME)
+    return val == val2 ? 0 : -2;
   else
     {
-      tree tcmp;
-
-      fold_defer_overflow_warnings ();
-
-      tcmp = fold_binary_to_constant (LT_EXPR, boolean_type_node, val, val2);
-
-      fold_undefer_and_ignore_overflow_warnings ();
-
-      if (!tcmp
-         || TREE_CODE (tcmp) != INTEGER_CST)
-       return -2;
-
-      if (!integer_zerop (tcmp))
+      int cmp = compare_values (val, val2);
+      if (cmp == -1)
        return 1;
+      else if (cmp == 0 || cmp == 1)
+       return 0;
+      else
+       return -2;
     }
 
   return 0;
@@ -958,8 +953,8 @@ compare_values_warnv (tree val1, tree va
 
   /* Convert the two values into the same type.  This is needed because
      sizetype causes sign extension even for unsigned types.  */
-  val2 = fold_convert (TREE_TYPE (val1), val2);
-  STRIP_USELESS_TYPE_CONVERSION (val2);
+  if (!useless_type_conversion_p (TREE_TYPE (val1), TREE_TYPE (val2)))
+    val2 = fold_convert (TREE_TYPE (val1), val2);
 
   const bool overflow_undefined
     = INTEGRAL_TYPE_P (TREE_TYPE (val1))
@@ -1067,32 +1062,43 @@ compare_values_warnv (tree val1, tree va
     }
   else
     {
-      tree t;
+      if (TREE_CODE (val1) == INTEGER_CST && TREE_CODE (val2) == INTEGER_CST)
+       {
+         /* We cannot compare overflowed values.  */
+         if (TREE_OVERFLOW (val1) || TREE_OVERFLOW (val2))
+           return -2;
+
+         return tree_int_cst_compare (val1, val2);
+       }
 
       /* First see if VAL1 and VAL2 are not the same.  */
-      if (val1 == val2 || operand_equal_p (val1, val2, 0))
+      if (operand_equal_p (val1, val2, 0))
        return 0;
 
+      fold_defer_overflow_warnings ();
+
       /* If VAL1 is a lower address than VAL2, return -1.  */
-      if (operand_less_p (val1, val2) == 1)
-       return -1;
+      tree t = fold_binary_to_constant (LT_EXPR, boolean_type_node, val1, 
val2);
+      if (t && integer_onep (t))
+       {
+         fold_undefer_and_ignore_overflow_warnings ();
+         return -1;
+       }
 
       /* If VAL1 is a higher address than VAL2, return +1.  */
-      if (operand_less_p (val2, val1) == 1)
-       return 1;
-
-      /* If VAL1 is different than VAL2, return +2.
-        For integer constants we either have already returned -1 or 1
-        or they are equivalent.  We still might succeed in proving
-        something about non-trivial operands.  */
-      if (TREE_CODE (val1) != INTEGER_CST
-         || TREE_CODE (val2) != INTEGER_CST)
+      t = fold_binary_to_constant (LT_EXPR, boolean_type_node, val2, val1);
+      if (t && integer_onep (t))
        {
-          t = fold_binary_to_constant (NE_EXPR, boolean_type_node, val1, val2);
-         if (t && integer_onep (t))
-           return 2;
+         fold_undefer_and_ignore_overflow_warnings ();
+         return 1;
        }
 
+      /* If VAL1 is different than VAL2, return +2.  */
+      t = fold_binary_to_constant (NE_EXPR, boolean_type_node, val1, val2);
+      fold_undefer_and_ignore_overflow_warnings ();
+      if (t && integer_onep (t))
+       return 2;
+
       return -2;
     }
 }

Reply via email to