It's OK to pass const pointers to __builtin_object_size(),
correct the documentation.
Signed-off-by: Jakub Kicinski <jakub.kicin...@netronome.com>
---
gcc/doc/extend.texi | 2 +-
1 file changed, 1 insertion(+), 1 deletion(-)
diff --git a/gcc/doc/extend.texi b/gcc/doc/extend.texi
index 0669f7999beb..4378ab84b5d8 100644
--- a/gcc/doc/extend.texi
+++ b/gcc/doc/extend.texi
@@ -10110,7 +10110,7 @@ follow pointer assignments through non-trivial control
flow they rely
on various optimization passes enabled with @option{-O2}. However, to
a limited extent, they can be used without optimization as well.
-@deftypefn {Built-in Function} {size_t} __builtin_object_size (void *
@var{ptr}, int @var{type})
+@deftypefn {Built-in Function} {size_t} __builtin_object_size (const void *
@var{ptr}, int @var{type})
is a built-in construct that returns a constant number of bytes from
@var{ptr} to the end of the object @var{ptr} pointer points to
(if known at compile time). @code{__builtin_object_size} never evaluates
--
1.9.1
