> If we have BIGGEST_ALIGNMENT=16 that means we have likely a 16 bit > architecture. I doubt that the strict alignment code makes any sense for > modesize> BIGGEST_ALIGNMENT.
Note that m68k is a 32-bit port (UNITS_PER_WORD is 4) but, by definition of BIGGEST_ALIGNMENT, not honoring an alignment larger than it is perfectly OK. -- Eric Botcazou
