------- Additional Comments From bangerth at dealii dot org 2004-12-21 17:36
-------
gcc is correct: the result of getSomething is a temporary. Temporaries can
only be bound to const references, not to non-const ones. Thus, the
constructor
UsePointer(Pointer<TEST> &point)
: m_localCopy(point)
{}
is not a candidate. In order to use the constructor
UsePointer(Pointer<TEST> point)
: m_localCopy(point)
{
}
you need to be able to copy objects of type Pointer<int>, but then you
run into the same problem of not having an appropriate copy constructor
of Pointer that takes a constant reference.
W.
--
What |Removed |Added
----------------------------------------------------------------------------
Status|UNCONFIRMED |RESOLVED
Resolution| |INVALID
http://gcc.gnu.org/bugzilla/show_bug.cgi?id=19112
