https://gcc.gnu.org/bugzilla/show_bug.cgi?id=124021
Peter Bergner <bergner at gcc dot gnu.org> changed:
What |Removed |Added
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CC| |bergner at gcc dot gnu.org
--- Comment #2 from Peter Bergner <bergner at gcc dot gnu.org> ---
(In reply to Richard Biener from comment #1)
> Or disallow vector in interrupt
That is possible for the interrupt function we compile, but we have no
control over any functions it might call. For instance, if the interrupt
function calls memset or memcpy, then that might under the covers use
vector instructions, so I think disallowing vector isn't really a
workable solution.
