https://gcc.gnu.org/bugzilla/show_bug.cgi?id=111272
--- Comment #8 from Paul Keir <pkeir at outlook dot com> --- I wonder if a small part of this bug still remains. The code below should #include <initializer_list>, but as it doesn't, we get an error message. The message now gives all the right information but, with -std=c++23 and -std=c++26, a part of the text is still truncated. Instead of "declared here" we get "is not usable as a 'constexpr' function because:". Perhaps it should also say "declared here" with -std=c++23 and -std=c++26. At https://godbolt.org/z/6c9hME7hh the code is: // #include <initializer_list> constexpr bool init_list() { int total{}; for (int x : {1, 2, 3}) total += x; return total == 6; } static_assert(init_list(), ""); The error message is: <source>: In function 'constexpr bool init_list()': <source>:6:24: error: deducing from brace-enclosed initializer list requires '#include <initializer_list>' +++ |+#include <initializer_list> 1 | // #include <initializer_list> ...... 6 | for (int x : {1, 2, 3}) | ^ <source>: At global scope: <source>:11:24: error: non-constant condition for static assertion 11 | static_assert(init_list(), ""); | ~~~~~~~~~^~ <source>:11:24: error: 'constexpr bool init_list()' called in a constant expression <source>:3:16: note: 'constexpr bool init_list()' is not usable as a 'constexpr' function because: 3 | constexpr bool init_list() | ^~~~~~~~~ Compiler returned: 1
