https://gcc.gnu.org/bugzilla/show_bug.cgi?id=111079
Bug ID: 111079 Summary: Failing to reject a defaulted/deleted local function definition if it is a friend of a local class Product: gcc Version: 14.0 Status: UNCONFIRMED Severity: normal Priority: P3 Component: c++ Assignee: unassigned at gcc dot gnu.org Reporter: janschultke at googlemail dot com Target Milestone: --- ## Code to Reproduce A (https://godbolt.org/z/ar34vn5dT) void foo() { struct A; bool operator ==(const A&, const A&); struct A { friend bool operator ==(const A&, const A&); }; bool operator ==(const A&, const A&) = default; } ## Code to Reproduce B (https://godbolt.org/z/sdo9fhacb) void foo() { struct A; bool bar(const A&, const A&); struct A { friend bool bar(const A&, const A&); }; bool bar(const A&, const A&) = delete; } ## Expected Output Compiler error. ## Actual Output <source>: In function 'void foo()': <source>:7:40: warning: declaration of 'bool operator==(const foo()::A&, const foo()::A&)' has 'extern' and is initialized 7 | bool operator ==(const A&, const A&) = default; | ## Explanation According to [dcl.fct.def.general] p2: > A function shall be defined only in namespace or class scope. There is a definition of `operator==` at block scope, which is obviously invalid. Operator overloads are also considered functions ([over.oper.general]), so they should be subject to the same rules.