https://gcc.gnu.org/bugzilla/show_bug.cgi?id=105580
Jonathan Wakely <redi at gcc dot gnu.org> changed: What |Removed |Added ---------------------------------------------------------------------------- Ever confirmed|0 |1 Assignee|unassigned at gcc dot gnu.org |redi at gcc dot gnu.org Status|UNCONFIRMED |ASSIGNED Last reconfirmed| |2023-03-31 --- Comment #4 from Jonathan Wakely <redi at gcc dot gnu.org> --- (In reply to Jason Merrill from comment #1) > Why does _M_get clear _M_sbuf? Because that's what the standard implies should happen: If the end of stream is reached (streambuf_type::sgetc() returns traits::eof()), the iterator becomes equal to the end-of-stream iterator value." charT operator*() const; 1 Returns: The character obtained via the streambuf member sbuf_->sgetc(). But this means that a dereferenceable iterator can become non-dereferenceable as a result of dereferencing it ... which seems very wrong indeed. It seems better to check for EOF on operator++ and only clear _M_sbuf in that function, but we need to basically rewrite the entire class (without ABI changes) to do that.