[Bug middle-end/104296] MIN should simplify to unsigned != 0

[pinskia at gcc dot gnu.org via Gcc-bugs]

https://gcc.gnu.org/bugzilla/show_bug.cgi?id=104296

Andrew Pinski <pinskia at gcc dot gnu.org> changed:

           What    |Removed                     |Added
----------------------------------------------------------------------------
   Last reconfirmed|                            |2022-12-09
           Assignee|unassigned at gcc dot gnu.org      |pinskia at gcc dot 
gnu.org
     Ever confirmed|0                           |1
             Status|UNCONFIRMED                 |ASSIGNED

--- Comment #1 from Andrew Pinski <pinskia at gcc dot gnu.org> ---
Mine.

Actually this should only be done in expand ...
And we should do:
  _1 = a_2(D) != 0;
  _3 = (unsigned intD.9) _1;

Into:
_3 = MIN_EXPR<a_2(D), 1>;

Instead.