https://gcc.gnu.org/bugzilla/show_bug.cgi?id=107813
--- Comment #3 from Grzegorz Drzewiecki <gdrzewo at gmail dot com> ---
(In reply to Jonathan Wakely from comment #1)
> When you call this->o << t then there is no exact match, so an implicit
> conversion to unsigned char happens.
OK. But what botter me. I've added global operator like:
std::ostream &operator<<(std::ostream &os, unsigned char c) {
return os << static_cast<unsigned int>(c);
}
With this one my example works fine:
f << cat << " vs " << dog << "\n\r";
stdout: 67 vs 68.
There is different conversion for either global operator or template operator.
