https://gcc.gnu.org/bugzilla/show_bug.cgi?id=107833
--- Comment #3 from Martin Liška <marxin at gcc dot gnu.org> ---
> Isn't there an uninitialized read from "i" here?
Yes ...
> At least on the second
> time through the outer loop, if (a < h) is true since 1 < 0.
>
> > c = *f;
> > }
> > for (h = 0; h < 3; h++) {
> > if (d)
> > break;
>
> d is nonzero so h will always be 0 in this function.
... but as you correctly said, it's never executed as 'a < h' is always false.
>
> > i--;
> > printf("0");
> > }
> > }
> > return 0;
> > }
>
> Unless I'm missing something....
