[Bug target/60778] shift not folded into shift on x86-64

[pinskia at gcc dot gnu.org via Gcc-bugs]

https://gcc.gnu.org/bugzilla/show_bug.cgi?id=60778

Andrew Pinski <pinskia at gcc dot gnu.org> changed:

           What    |Removed                     |Added
----------------------------------------------------------------------------
   Last reconfirmed|2014-04-08 00:00:00         |2021-9-26

--- Comment #2 from Andrew Pinski <pinskia at gcc dot gnu.org> ---
Trying 7 -> 8:
    7: {r87:DI=r89:DI>>0x3;clobber flags:CC;}
      REG_DEAD r89:DI
      REG_UNUSED flags:CC
    8: r88:DF=[r87:DI*0x8+`mem']
      REG_DEAD r87:DI
Failed to match this instruction:
(set (reg:DF 88 [ mem[_1] ])
    (mem:DF (plus:DI (and:DI (reg:DI 89)
                (const_int -8 [0xfffffffffffffff8]))
            (symbol_ref:DI ("mem") [flags 0x2]  <var_decl 0x7f6b6efd9c60 mem>))
[1 mem[_1]+0 S8 A64]))

We have 2->2 combine now but it looks like we don't try to split inside a mem
...