https://gcc.gnu.org/bugzilla/show_bug.cgi?id=89727
Richard Biener <rguenth at gcc dot gnu.org> changed:
What |Removed |Added
----------------------------------------------------------------------------
Keywords| |wrong-code
Status|UNCONFIRMED |NEW
Last reconfirmed| |2019-03-15
Ever confirmed|0 |1
--- Comment #1 from Richard Biener <rguenth at gcc dot gnu.org> ---
.original shows the difference:
struct B b;
<<cleanup_point <<< Unknown tree: expr_stmt
(void) std::basic_ostream<char>::operator<< ((struct __ostream_type *)
std::basic_ostream<char>::operator<< ((struct basic_ostream *)
std::basic_ostream<char>::operator<< (&cout, a.i), endl), flush) >>>>>;
<<cleanup_point <<< Unknown tree: expr_stmt
(void) std::basic_ostream<char>::operator<< ((struct basic_ostream *)
std::basic_ostream<char>::operator<< (&cout, _ZTWN1B1aE ()->i), endl) >>>>>;
<<cleanup_point <<< Unknown tree: expr_stmt
(void) std::basic_ostream<char>::operator<< ((struct basic_ostream *)
std::basic_ostream<char>::operator<< (&cout, a.i), endl) >>>>>;
note how we perform the access differently for B::a.i vs. b.a.i,
unexpected to me.
