https://gcc.gnu.org/bugzilla/show_bug.cgi?id=84580
Jonathan Wakely <redi at gcc dot gnu.org> changed:
What |Removed |Added
----------------------------------------------------------------------------
Status|UNCONFIRMED |NEW
Last reconfirmed| |2018-02-27
Ever confirmed|0 |1
--- Comment #2 from Jonathan Wakely <redi at gcc dot gnu.org> ---
This change would meet the standard's requirement that a != b is equivalent to
!(a == b)
--- a/libstdc++-v3/include/debug/vector
+++ b/libstdc++-v3/include/debug/vector
@@ -725,7 +725,7 @@ namespace __debug
inline bool
operator!=(const vector<_Tp, _Alloc>& __lhs,
const vector<_Tp, _Alloc>& __rhs)
- { return __lhs._M_base() != __rhs._M_base(); }
+ { return !(__lhs == __rhs); }
template<typename _Tp, typename _Alloc>
inline bool
It would change the behaviour for this program:
#include <debug/vector>
#include <cassert>
struct foo { };
bool operator!=(std::vector<foo*> const& v1, std::vector<foo*> const& v2)
{ return &v1 != &v2; }
int main()
{
__gnu_debug::vector<foo*> v1, v2;
assert(v1 != v2);
}
Currently the operator!= for debug vectors calls the program-defined overload
for std::vectors, but with the patch above it would call operator== for debug
vectors which calls the standard operator== for std::vectors. This is probably
OK, the program above is pathologically contrived, and meeting the standard
requirements when _GLIBCXX_DEBUG is defined is more important, so that
_GLIBCXX_DEBUG doesn't change semantics.
