https://gcc.gnu.org/bugzilla/show_bug.cgi?id=83710
--- Comment #5 from Andrew Pinski <pinskia at gcc dot gnu.org> --- (In reply to Chanpreet Singh from comment #4) > (In reply to Andrew Pinski from comment #3) > > For imull discussion see > > https://stackoverflow.com/questions/42587607/why-is-imul-used-for- > > multiplying-unsigned-numbers . > > I understand that. However, can you point to me what made the compiler > choose shrl instruction over sarl? Again: unsigned * int produces a type of unsigned. And then the shift is done in unsigned type. See comment #1. imull is used for both signed and unsigned multiply :).
