https://gcc.gnu.org/bugzilla/show_bug.cgi?id=78657
Bug ID: 78657
Summary: Using macro with _Pragma gives error: '#pragma' is not
allowed here
Product: gcc
Version: 5.4.0
Status: UNCONFIRMED
Severity: normal
Priority: P3
Component: c
Assignee: unassigned at gcc dot gnu.org
Reporter: jquinsey at entrenet dot com
Target Milestone: ---
The following two-line source file test.c:
#define FOO _Pragma("GCC diagnostic push") 42
int foo = FOO;
gives:
gcc test.c -E
# 1 "test.c"
# 1 "<built-in>"
# 1 "<command-line>"
# 1 "test.c"
int foo =
# 2 "test.c"
#pragma GCC diagnostic push
# 2 "test.c"
42;
gcc test.c
test.c:2:1: error: expected expression before '#pragma'
int foo = FOO;
^
g++ -x c++ test.c
test.c:2:1: error: '#pragma' is not allowed here
int foo = FOO;
^
This appears to be consistent across many versions of gcc and g++. For example,
5.4.0 from Cygwin, 5.1 from this test sample at http://ideone.com/6unk5c, and
versions 4.4 through to 6.2 and 7 at https://godbolt.org/.
The icc and clang compilers (from 3.2 upwards) seem handle this correctly.
The text within the _Pragma doesn't seem relevant. Reversing the order of the
two parts of the macro gives a slightly different error message for C:
error: expected ',' or ';' before '#pragma'
