https://gcc.gnu.org/bugzilla/show_bug.cgi?id=71802
Bug ID: 71802 Summary: gcc ICE at -O3 on valid code on x86_64-linux-gnu in expand_LOOP_VECTORIZED Product: gcc Version: 7.0 Status: UNCONFIRMED Severity: normal Priority: P3 Component: tree-optimization Assignee: unassigned at gcc dot gnu.org Reporter: helloqirun at gmail dot com Target Milestone: --- The following valid code causes an ICE when compiled with the current gcc trunk at only -O3 on x86_64-linux-gnu in both 32- and 64-bit modes. It appears to be a 7 regression. $ gcc-trunk -v Using built-in specs. COLLECT_GCC=gcc-trunk COLLECT_LTO_WRAPPER=/home/absozero/trunk/root-gcc/libexec/gcc/x86_64-pc-linux-gnu/7.0.0/lto-wrapper Target: x86_64-pc-linux-gnu Configured with: ../gcc/configure --prefix=/home/absozero/trunk/root-gcc --enable-languages=c,c++ --disable-werror --enable-multilib Thread model: posix gcc version 7.0.0 20160707 (experimental) [trunk revision 238108] (GCC) $ gcc-trunk -O3 abc.c abc.c: In function ‘fn1’: abc.c:26:7: warning: assignment from incompatible pointer type [-Wincompatible-pointer-types] i = &h; ^ abc.c:28:7: warning: assignment from incompatible pointer type [-Wincompatible-pointer-types] i = &f; ^ abc.c:3:6: internal compiler error: in expand_LOOP_VECTORIZED, at internal-fn.c:1944 void fn1() { ^~~ 0x969f07 expand_LOOP_VECTORIZED ../../gcc/gcc/internal-fn.c:1944 0x75a117 expand_call_stmt ../../gcc/gcc/cfgexpand.c:2573 0x75a117 expand_gimple_stmt_1 ../../gcc/gcc/cfgexpand.c:3574 0x75a117 expand_gimple_stmt ../../gcc/gcc/cfgexpand.c:3740 0x75d700 expand_gimple_basic_block ../../gcc/gcc/cfgexpand.c:5747 0x7624c6 execute ../../gcc/gcc/cfgexpand.c:6362 Please submit a full bug report, with preprocessed source if appropriate. Please include the complete backtrace with any bug report. See <http://gcc.gnu.org/bugs.html> for instructions. $ cat abc.c int b, c; long d, f; void fn1() { char g; long long h = 0; int *i; if (0) { L2: b && (b = f); d = 3; for (; d;) { char *j = &g; c = *j = 0; L3: *j %= b; for (; g <= 4;) ; } goto L2; } for (; *i; *i = 1) { if ((h -= 4) == (h != (b ?: d))) { g = 3; goto L3; } i = &h; *i = f; i = &f; if ((h && 6) - (h = 0)) goto L2; } for (; d;) goto L3; }