https://gcc.gnu.org/bugzilla/show_bug.cgi?id=67253
Bug ID: 67253
Summary: ICE at -O3 on x86_64-linux-gnu (verify_gimple failed)
Product: gcc
Version: 6.0
Status: UNCONFIRMED
Severity: normal
Priority: P3
Component: tree-optimization
Assignee: unassigned at gcc dot gnu.org
Reporter: su at cs dot ucdavis.edu
Target Milestone: ---
The following code causes an ICE when compiled with the current gcc trunk at
-O3 on x86_64-linux-gnu in both 32-bit and 64-bit modes.
It is a regression from 5.1.x.
$ gcc-trunk -v
Using built-in specs.
COLLECT_GCC=gcc-trunk
COLLECT_LTO_WRAPPER=/usr/local/gcc-trunk/libexec/gcc/x86_64-pc-linux-gnu/6.0.0/lto-wrapper
Target: x86_64-pc-linux-gnu
Configured with: ../gcc-trunk/configure --prefix=/usr/local/gcc-trunk
--enable-languages=c,c++ --disable-werror --enable-multilib
Thread model: posix
gcc version 6.0.0 20150815 (experimental) [trunk revision 226911] (GCC)
$
$ gcc-trunk -O2 small.c; ./a.out
$ gcc-5.1 -O3 small.c; ./a.out
$
$ gcc-trunk -O3 small.c
small.c: In function ‘fn2.constprop’:
small.c:45:1: error: location references block not in block tree
fn2 (char p1, int p2, int *p3)
^
&c
p3_277 = &c;
small.c:45:1: internal compiler error: verify_gimple failed
0xae9db2 verify_gimple_in_cfg(function*, bool)
../../gcc-trunk/gcc/tree-cfg.c:5101
0x9e35a7 execute_function_todo
../../gcc-trunk/gcc/passes.c:1948
0x9e3e53 execute_todo
../../gcc-trunk/gcc/passes.c:2005
Please submit a full bug report,
with preprocessed source if appropriate.
Please include the complete backtrace with any bug report.
See <http://gcc.gnu.org/bugs.html> for instructions.
$
--------------------------
int *a, b, c, **d = &a, e, f, **h, i, j, k, l, m, *n, o, **q, r, s;
void fn1 (int p) { }
void
fn3 ()
{
for (; j; j++)
for (; k; k++)
l++;
f++;
}
static int
fn4 (char p1, int *p2)
{
for (; m < 1;)
{
fn1 (q == &p2);
for (; o; o++)
;
n = p2;
return 0;
}
for (;;)
{
for (; s; s++)
b = r;
*d = 0;
}
}
static int *fn2 (char, int, int *);
static int
fn5 ()
{
int *g = &c;
fn3 ();
fn2 (0, 0, g);
return e;
}
static int *
fn2 (char p1, int p2, int *p3)
{
fn4 (0, p3);
fn1 (&p3 == h);
for (; i;)
fn5 ();
fn4 (0, p3);
return *d;
}
int
main ()
{
fn5 ();
return 0;
}