https://gcc.gnu.org/bugzilla/show_bug.cgi?id=67253
Bug ID: 67253 Summary: ICE at -O3 on x86_64-linux-gnu (verify_gimple failed) Product: gcc Version: 6.0 Status: UNCONFIRMED Severity: normal Priority: P3 Component: tree-optimization Assignee: unassigned at gcc dot gnu.org Reporter: su at cs dot ucdavis.edu Target Milestone: --- The following code causes an ICE when compiled with the current gcc trunk at -O3 on x86_64-linux-gnu in both 32-bit and 64-bit modes. It is a regression from 5.1.x. $ gcc-trunk -v Using built-in specs. COLLECT_GCC=gcc-trunk COLLECT_LTO_WRAPPER=/usr/local/gcc-trunk/libexec/gcc/x86_64-pc-linux-gnu/6.0.0/lto-wrapper Target: x86_64-pc-linux-gnu Configured with: ../gcc-trunk/configure --prefix=/usr/local/gcc-trunk --enable-languages=c,c++ --disable-werror --enable-multilib Thread model: posix gcc version 6.0.0 20150815 (experimental) [trunk revision 226911] (GCC) $ $ gcc-trunk -O2 small.c; ./a.out $ gcc-5.1 -O3 small.c; ./a.out $ $ gcc-trunk -O3 small.c small.c: In function ‘fn2.constprop’: small.c:45:1: error: location references block not in block tree fn2 (char p1, int p2, int *p3) ^ &c p3_277 = &c; small.c:45:1: internal compiler error: verify_gimple failed 0xae9db2 verify_gimple_in_cfg(function*, bool) ../../gcc-trunk/gcc/tree-cfg.c:5101 0x9e35a7 execute_function_todo ../../gcc-trunk/gcc/passes.c:1948 0x9e3e53 execute_todo ../../gcc-trunk/gcc/passes.c:2005 Please submit a full bug report, with preprocessed source if appropriate. Please include the complete backtrace with any bug report. See <http://gcc.gnu.org/bugs.html> for instructions. $ -------------------------- int *a, b, c, **d = &a, e, f, **h, i, j, k, l, m, *n, o, **q, r, s; void fn1 (int p) { } void fn3 () { for (; j; j++) for (; k; k++) l++; f++; } static int fn4 (char p1, int *p2) { for (; m < 1;) { fn1 (q == &p2); for (; o; o++) ; n = p2; return 0; } for (;;) { for (; s; s++) b = r; *d = 0; } } static int *fn2 (char, int, int *); static int fn5 () { int *g = &c; fn3 (); fn2 (0, 0, g); return e; } static int * fn2 (char p1, int p2, int *p3) { fn4 (0, p3); fn1 (&p3 == h); for (; i;) fn5 (); fn4 (0, p3); return *d; } int main () { fn5 (); return 0; }