https://gcc.gnu.org/bugzilla/show_bug.cgi?id=64021
Jakub Jelinek <jakub at gcc dot gnu.org> changed:
What |Removed |Added
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CC| |jakub at gcc dot gnu.org
--- Comment #5 from Jakub Jelinek <jakub at gcc dot gnu.org> ---
Isn't that just because in C++ empty structs are forced by the FE into having
length of one byte? I mean, if you:
struct S {};
int a = sizeof (struct S);
struct S b;
then in C it is int a = 0; and b is a common with zero size, while in C++ it is
int a = 1; and b has size 1. So it is natural that those two (which are very
much different thing) are passed differently, I don't see anything to change on
that. So, for go, the question is if it follows GNU C or C++ for empty
structs.
