https://gcc.gnu.org/bugzilla/show_bug.cgi?id=62086
--- Comment #1 from Andrew Pinski <pinskia at gcc dot gnu.org> --- (In reply to baoshan from comment #0) > For this simple code, it would compile without -fextended-identifiers but > fail with it: I think this is correct behavior as the C standard requires the #if 0 code to be tokenized still. In the case without -fextended-identifiers: /u00A8 are three different tokens, / u and 00A8 (all three different tokens). With -fextended-identifiers \u00A8\u00AA\u00AD\u00AF\u00B2\u00B5 is considered one token (an identifier) but the characters not valid for the identifier.
