http://gcc.gnu.org/bugzilla/show_bug.cgi?id=57021

Manuel López-Ibáñez <manu at gcc dot gnu.org> changed:

           What    |Removed                     |Added
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                 CC|                            |manu at gcc dot gnu.org

--- Comment #2 from Manuel López-Ibáñez <manu at gcc dot gnu.org> 2013-04-21 
12:57:45 UTC ---
(In reply to comment #0)
> Really we should say instead a is not a type.  Yes this is a complex error
> recovery issue but I think we should be able to figure it out.

I think that would be difficult, since by the time ")" is parsed, we are
already assuming that this is a binary expression. 

Nonetheless, I don't see why it is better to assume that "a" is a type than to
assume that the user wanted to type "(a * 0)".

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