http://gcc.gnu.org/bugzilla/show_bug.cgi?id=52901
Jonathan Wakely <redi at gcc dot gnu.org> changed:
What |Removed |Added
----------------------------------------------------------------------------
Status|UNCONFIRMED |RESOLVED
Resolution| |INVALID
--- Comment #2 from Jonathan Wakely <redi at gcc dot gnu.org> 2012-04-08
14:14:30 UTC ---
This is just a bug in your program, not G++
(In reply to comment #0)
>
> X&& f() {
> X x;
> return std::move(x);
> }
This function is unsafe, it returns a reference to a local variable. You
probably meant it to return X not X&&
It is effectively the same as:
X& f() {
X x;
return x;
}
(except G++ warns about that, because it's simpler)
>
> int main() {
> cout << "Hello References [1]" << std::endl;
> X x0 = f();
> cout << "x0: " << x0.value << std::endl;
> X&& x1 = f();
This reference is bound to a variable that went out of scope when f() returned.
> cout << "No copy construction or assignment expected" << std::endl;
> cout << "x1: " << x1.value << std::endl;
This accesses deallocated memory.
N.B. you don't even need to use std::move, the compiler will automatically
select the move constructor to create the return value here:
X f()
{
X x;
return x;
}