http://gcc.gnu.org/bugzilla/show_bug.cgi?id=52757
--- Comment #1 from Jonathan Wakely <redi at gcc dot gnu.org> 2012-03-28 19:58:41 UTC --- (In reply to comment #0) > that this happens because there is no constexpr conversion operator from the > lambda function type to the corresponding function pointer type Is there supposed to be? "The closure type for a lambda-expression with no lambda-capture has a public non-virtual non-explicit const conversion function to pointer to function having the same parameter and return types as the closure type's function call operator. The value returned by this conversion function shall be the address of a function that, when invoked, has the same effect as invoking the closure type's function call operator." A closure is not literal and its conversion operator isn't constexpr.
