http://gcc.gnu.org/bugzilla/show_bug.cgi?id=49734

--- Comment #2 from Jonathan Wakely <redi at gcc dot gnu.org> 2011-07-13 
14:29:35 UTC ---
You probably want to use the return value:

    add = std::for_each(l, l + 5, add);

Although for this specific case you could #include <numeric> and use
std::accumulate

    int acc = std::accumulate(c, c + 5, 0);

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