http://gcc.gnu.org/bugzilla/show_bug.cgi?id=48651
--- Comment #2 from Jerry DeLisle <jvdelisle at gcc dot gnu.org> 2011-04-17
18:28:55 UTC ---
hmm, notice the typo! i have set ldnum to 0.0 but it still is printing the
value of dnum. What am I doing wrong.
$ cat sprint.c
#include <stdio.h>
int
main ()
{
float num = 0.9;
double dnum = 0.9;
long double ldnum = 25.6;
printf("%50.48f\n", num);
printf("%50.48lf, %d\n", num, sizeof(num));
printf("%80.78f\n", dnum);
printf("%80.78lf, %d\n", dnum, sizeof(dnum));
printf("%80.78f\n", ldnum);
printf("%80.78lf, %d\n", ldnum, sizeof(ldnum));
}
[jerry@quattro pr48602]$ cat sprint.c
#include <stdio.h>
int
main ()
{
float num = 0.9;
double dnum = 0.9;
long double ldnum = 25.6;
printf("%50.48f\n", num);
printf("%50.48lf, %d\n", num, sizeof(num));
printf("%80.78f\n", dnum);
printf("%80.78lf, %d\n", dnum, sizeof(dnum));
printf("%80.78f\n", ldnum);
printf("%80.78lf, %d\n", ldnum, sizeof(ldnum));
}
[jerry@quattro pr48602]$ ./a.out
0.899999976158142089843750000000000000000000000000
0.899999976158142089843750000000000000000000000000, 4
0.900000000000000022204460492503130808472633361816406250000000000000000000000000
0.900000000000000022204460492503130808472633361816406250000000000000000000000000,
8
0.900000000000000022204460492503130808472633361816406250000000000000000000000000
0.900000000000000022204460492503130808472633361816406250000000000000000000000000,
16
The value of ldnum is not surviving.
