http://gcc.gnu.org/bugzilla/show_bug.cgi?id=48580
Summary: missed optimization: integer overflow checks Product: gcc Version: 4.6.0 Status: UNCONFIRMED Severity: enhancement Priority: P3 Component: rtl-optimization AssignedTo: unassig...@gcc.gnu.org ReportedBy: za...@panix.com To the best of my knowledge, this is the only safe way (without -fwrapv) to check whether the product of two signed integers overflowed: bool product_does_not_overflow(signed x, signed y) { unsigned tmp = x * unsigned(y); return signed(tmp) > 0 && tmp / x == unsigned(y); } (I believe C and C++ are the same in this regard but I could be wrong. If there is a better way to write this test I would love to know about it.) g++ 4.6 produces this assembly dump on x86-64: _Z25product_does_not_overflowii: movl %esi, %edx xorl %eax, %eax imull %edi, %edx testl %edx, %edx jle .L2 movl %edx, %eax xorl %edx, %edx divl %edi cmpl %eax, %esi sete %al .L2: rep ret but, if I understand the semantics of IMUL correctly, it could do this instead: _Z25product_does_not_overflowii: xorl %eax, %eax imull %edi, %esi setno %al ret which is a pretty substantial micro-win, particularly in getting rid of a divide.