------- Comment #2 from mark at gcc dot gnu dot org 2009-08-18 08:11 ------- (In reply to comment #1) > Wait a second are you saying: > volatile char * p_name > > and p_name disappears? > Well that is because p_name is no longer volatile but what it points to is.
Well, obvious p_name still is there, since it will be put in a register to feed into the asm statement. But the debuginfo location for it is missing. > I don't think this is a bug in GCC but rather a misunderstanding on how > qualifiers apply to types. > > If you use a typedef for char*, does it disappear? You are right, I misunderstood how the volatile qualifier "attached" to the type. Using: typedef char * char_ptr; volatile char_ptr p_name = (char_ptr) name; Does what I want. Thanks. That will allow me to write a workaround for what I am seeing using typedef typeof(arg). I am not sure this means the bug is really not there, because I am still a little surprised (confused?) the location expression goes missing in the original (and I assume the variable isn't actually fully optimized away). But since I now have a workaround for that I am already happy. Thanks. -- http://gcc.gnu.org/bugzilla/show_bug.cgi?id=41097
