On Fri, Jan 16, 2009 at 10:30 AM, rguenth at gcc dot gnu dot org <gcc-bugzi...@gcc.gnu.org> wrote: > > (void *)((intptr_t)&iptr + (intptr_t)p - (intptr_t)&iptr) > > <==> > > (void *)(intptr_t)p > > which is guaranteed by the std
No that is not guaranteed because of: If the result cannot be represented in the integer type, the behavior is undefined. The result need not be in the range of values of any integer type. :).
