Locale constructor
locale(const locale& other, const locale& one, locale::category cats)
creates named locale when 'other' - named locale, but 'one' - unnamed.
According to 22.1.1 p8:
A locale constructed from a name string (such as "POSIX"), or from parts of two
named locales, has a name; all others do not.
Example:
[test.cpp]
#include <locale>
#include <iostream>
using namespace std;
int main()
{
locale other(locale("C"));
locale one(locale("en_US"), new ctype<char>());
locale loc(other, one, locale::collate);
cout << "one.name() is " << one.name() << endl;
cout << "other.name() is " << other.name() << endl;
cout << "loc.name() is " << loc.name() << endl;
return 0;
}
[EMAIL PROTECTED] locale_name]$ g++ test.cpp && ./a.out
one.name() is *
other.name() is C
loc.name() is C
[EMAIL PROTECTED] locale_name]$ g++ --version
g++ (GCC) 4.3.0 20080428 (Red Hat 4.3.0-8)
Copyright (C) 2008 Free Software Foundation, Inc.
This is free software; see the source for copying conditions. There is NO
warranty; not even for MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.
--
Summary: Locale, constructed from named and unnamed locales,
become named
Product: gcc
Version: unknown
Status: UNCONFIRMED
Severity: normal
Priority: P3
Component: libstdc++
AssignedTo: unassigned at gcc dot gnu dot org
ReportedBy: tsyvarev at ispras dot ru
http://gcc.gnu.org/bugzilla/show_bug.cgi?id=38365
