------- Comment #1 from pinskia at gcc dot gnu dot org 2008-08-03 20:32 ------- That is correct. % is not really the modulo operator but instead the remainder operator :). So (-a) %b is the same as -(a%b).
-- pinskia at gcc dot gnu dot org changed: What |Removed |Added ---------------------------------------------------------------------------- Status|UNCONFIRMED |RESOLVED Resolution| |INVALID http://gcc.gnu.org/bugzilla/show_bug.cgi?id=37015