The following program fails to compile:
template<typename T> void f()
{}
void g1() {}
void g2() {}
typedef void(*ptrType)();
int main(int argc, char** argv)
{
ptrType p = argc == 1 ? &f<char> : &f<int>; //<-- error
ptrType p2 = argc == 1 ? &g1 : &g2;
ptrType p1;
if (argc== 1)
p1 = &f<char>;
else
p1 = &f<int>;
}
fptr.cpp:11: error: address of overloaded function with no contextual type
information
As f<char> and f<int> are the same pointer-type, this shouldn't fail. It
doesn't fail for non-template-functions and it aslo doesn't fail if an
if/else-clause is used.
tried with gcc-4.3.1, 4.2.4 and 4.1.2 on x86_64 and 4.2.3 on powerpc-uclibc
--
Summary: compilation fails when pointer to template-functions are
returned by ?-operator
Product: gcc
Version: 4.2.3
Status: UNCONFIRMED
Severity: normal
Priority: P3
Component: c++
AssignedTo: unassigned at gcc dot gnu dot org
ReportedBy: rbuergel at web dot de
http://gcc.gnu.org/bugzilla/show_bug.cgi?id=36805
