------- Comment #5 from furue at hawaii dot edu 2008-01-31 02:45 ------- Subject: Re: illegal E format descriptor produces wrong output
| There is no restriction in F95 that d must be positive in Ew.d. | In 10.6.5.1, it clearly states that k = 0 at the beginning of | execution of an input/output statement. The wording you quote | above is (almost) identical to F95 language, so one could argue | that the -d < k <= 0 is true when d = 0 and k = 0. I may be missing something, but "-d < k <= 0" doesn't hold when d = 0 and k = 0. Notice the inequality "<". So, when k = 0, how should we read the part we quote? | In any event, gfortran is definitely giving a bogus answer | of 0E+1, and your desired output of ******* is probably the | right thing to do. I like that. But, for the sake of curiosity, how does the Fortran standard describe the process that leads to *******? I mean, suppose E8.0 is legal, but still can we emit *******? Ryo -- http://gcc.gnu.org/bugzilla/show_bug.cgi?id=35036
