------- Comment #1 from pinskia at gcc dot gnu dot org 2006-12-18 09:39 -------
No, this is undefined code.
since n is a signed type, and the starting n is 1 and it is only multiplied by
2, then it can only be postive and never equal to 0 because overflow for signed
types is undefined.
--
pinskia at gcc dot gnu dot org changed:
What |Removed |Added
----------------------------------------------------------------------------
Status|UNCONFIRMED |RESOLVED
Resolution| |INVALID
http://gcc.gnu.org/bugzilla/show_bug.cgi?id=30245
