------- Comment #18 from fxcoudert at gcc dot gnu dot org 2006-10-31 16:46 ------- (In reply to comment #16) > I understood that remainder (a, b) = a - round (a/b) * b, whereas > mod (a, b) = a - int (a/b) * b > and modulo (a, b) = a - floor (a/b) * b
Right you are, master. :) -- http://gcc.gnu.org/bugzilla/show_bug.cgi?id=24518
