------- Comment #5 from lukew at radterm dot com dot au 2006-10-26 06:45 ------- (In reply to comment #3) > Subject: Re: hex and oct constants are converted to > wrong type
> The resulting tokens compose the controlling constant expression which > is evaluated according to the rules of 6.6. For the purposes of this > token conversion and evaluation, all signed integer types and all > unsigned integer types act as if they have the same representation as, > respectively, the types intmax_t and uintmax_t defined in the header > <stdint.h>.142) > > 142) Thus, on an implementation where INT_MAX is 0x7FFF and UINT_MAX is > 0xFFFF, the constant 0x8000 is signed and positive within a #if > expression even though it would be unsigned in translation phase 7. > I don't get it. How can 0x8000 be signed AND positive when INT_MAX is a 16 bit integer? -- http://gcc.gnu.org/bugzilla/show_bug.cgi?id=27195
