GCC will accept the following code without warning even with -W -Wall -ansi
-pedantic:
#include <stdio.h>
int main(void)
{
int i;
i = 0;
while(1) {
printf("%d\n", i++);
if (i == 20) break;
} while(i < 10);
return 0;
}
This program will print all the way too 19 because the exit condition at the
end is ignored.
--
Summary: GCC accepts invalid loop syntax
Product: gcc
Version: 3.4.5
Status: UNCONFIRMED
Severity: minor
Priority: P3
Component: c
AssignedTo: unassigned at gcc dot gnu dot org
ReportedBy: copx at gmx dot net
http://gcc.gnu.org/bugzilla/show_bug.cgi?id=28446
