See below; G++ appears to correctly handle the use of 'struct B' to declare the
function template g(), but if there is no prior declaration of the class (as in
the declaration of f()), the class is erroneously taken as a class template.
extern "C" int printf( const char*, ... );
struct B{ int n; B(int n_) : n(n_){} };
template<class T> struct B g() // OK, g() returns B
{
return B(32);
}
template<class T> struct A f(); // OK, f() returns A
struct A { char c; A(char c_) : c(c_){}};
template<class T> struct A f()
{
return A('x');
}
int main( )
{
(void) printf( "%d, %c\n",
g<double>().n,
f<float>().c ); // prints "32, x\n".
return 0;
}
--
Summary: Non-template class function return type taken as
template when declared in a function template's return
type
Product: gcc
Version: 4.0.1
Status: UNCONFIRMED
Severity: normal
Priority: P3
Component: c++
AssignedTo: unassigned at gcc dot gnu dot org
ReportedBy: widman at gimpel dot com
http://gcc.gnu.org/bugzilla/show_bug.cgi?id=28044
