Hi, My system is a macbook pro (intel duo core) with standard install of OS X. GCC version 4.01 Build 5250.
I am writing a flex program and ran across a very strange issue. When building and running the following flex (lex) program, the global variable access does not work properly. The expected output from this program (when the a character is found) is : glo = 5 5 = ret, glo = 5 but when building/running this program using GCC 4.01 , I get this output: glo = 5 5 = ret, glo = 0 It works well with GCC v3.x Here is the simple lex program: %{ #include <stdio.h> #define yywrap() 1 int glo; %} %% "a" { glo = 5; printf("glo = %d\n", glo); return (int)5; } %% main () { printf("%d = ret, glo = %d", yylex(), glo); } To build this, I am running: flex test.l gcc lex.yy.c to run, a.out Then press the a key and enter. -- Summary: compiling very simple flex generated code results in global variabl error with GCC 4.0.1 Product: gcc Version: 4.0.1 Status: UNCONFIRMED Severity: critical Priority: P3 Component: c AssignedTo: unassigned at gcc dot gnu dot org ReportedBy: jesser at pixelworks dot com GCC build triplet: GCC version 4.0.1 build 5250 GCC host triplet: MacBookPro OSX GCC target triplet: MacBookPro OSX i686-apple-darwin8 http://gcc.gnu.org/bugzilla/show_bug.cgi?id=27646