FYI

With the help of the SQL database I am using now for CAS integration tests, 
I was able to generate 
some more interesting observations. Added new statistic section called 
"Performance based on Rubi rules"

  
<https://12000.org/my_notes/CAS_integration_tests/reports/summer_2022/indexchapter1.htm#x2-50001.3>
 
<https://12000.org/my_notes/CAS_integration_tests/reports/summer_2022/indexchapter1.htm#x2-50001.3>
 

 This section basically looks at how percentage solved by each CAS 
correlate to how 
many rules and how many steps Rubi itself used to solve the same integral. 
I also added histograms 
showing distribution of leaf size of anti-derivatives for each CAS. 

 Hope this is something that is useful to see.

--Nasser

On Saturday, September 24, 2022 at 9:09:24 AM UTC-5 Waldek Hebisch wrote:

> On Thu, Sep 22, 2022 at 04:37:21AM -0700, 'Nasser M. Abbasi' via FriCAS - 
> computer algebra system wrote:
> > Fyi, 
> > 
> > CAS integrations tests SQL database is now fully build.
> > 
>
> Thanks for the database. I looked at result in terms of Rubi
> steps and FriCAS performace is decreasing with number of Rubi
> steps (first is number of steps, second is fraction solved
> by FriCAS):
>
> [1.0, 0.8345051379_1238507301]
> [2.0, 0.8338310374 <(833)%20831-0374>_7230517291]
> [3.0, 0.8501565276_2501057619]
> [4.0, 0.8362068965_5172413793 <(517)%20241-3793>]
> [5.0, 0.8186005976 <(818)%20600-5976>_0956175299]
> [6.0, 0.8175120430 <(817)%20512-0430>_7169169736 <(716)%20916-9736>]
> [7.0, 0.7909229984_7016828149 <(701)%20682-8149>]
> [8.0, 0.7562585343_6504324078 <(650)%20432-4078>]
> [9.0, 0.7237969676_994067238]
> [10.0, 0.6470033034_4502123643 <(450)%20212-3643>]
> [11.0, 0.6482444733_4200260078]
> [12.0, 0.6384388807_0692194404]
> [13.0, 0.6023007395 <(602)%20300-7395>_2341824158]
> [14.0, 0.6090225563_9097744361 <(909)%20774-4361>]
> [15.0, 0.5511288180_6108897742 <(610)%20889-7742>]
> [16.0, 0.6092307692 <(609)%20230-7692>_3076923077]
> [17.0, 0.5546719681_9085487078 <(908)%20548-7078>]
> [18.0, 0.5558510638_2978723404]
> [19.0, 0.5223880597 <(522)%20388-0597>_0149253731]
> [20.0, 0.5607843137_2549019608 <(254)%20901-9608>]
>
>
> BTW: I am not sure how you maintain "has_known_anti". The following
> 9 have has_known_anti = 0, but belong to well-known class having
> elementary integrals:
>
> integrate(cos(d*x+c)^4/(a+b*sin(d*x+c)^3)^2,x, algorithm="fricas")
> integrate(cos(d*x+c)^2/(a+b*sin(d*x+c)^3)^2,x, algorithm="fricas")
> integrate(1/(a+b*sin(d*x+c)^3)^2,x, algorithm="fricas")
> integrate(sec(d*x+c)^2/(a+b*sin(d*x+c)^3)^2,x, algorithm="fricas")
> integrate(sec(d*x+c)^4/(a+b*sin(d*x+c)^3)^2,x, algorithm="fricas")
> integrate(sinh(d*x+c)^3/(a+b*tanh(d*x+c)^3),x, algorithm="fricas")
> integrate(sinh(d*x+c)/(a+b*tanh(d*x+c)^3),x, algorithm="fricas")
> integrate(csch(d*x+c)/(a+b*tanh(d*x+c)^3),x, algorithm="fricas")
> integrate(csch(d*x+c)^3/(a+b*tanh(d*x+c)^3),x, algorithm="fricas")
>
> FriCAS, Maple and almost surely MMa can do them. I suspect that
> Maple or MMa answer is nicer, so you can use it as optimal one.
> There is buch of others, one would have to check if they are correct.
> But the above are easy ones.
>
> -- 
> Waldek Hebisch
>

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