Hi, (I didn't receive this message in mailbox, strange...)
I searched through source files, and found that riemannZeta is purely symbolic, you can not evaluate it numerically at all. - Best, - Qian On Sunday, April 17, 2022 at 3:21:13 AM UTC+8 [email protected] wrote: > Hey guys > > I'm a newbie learning FriCAS and I have a question about 'package-calling' > a function. > > Exploring the library I've tried using riemannZeta, but the exposed > version seems to be a category (HyperDoc tells me that it comes from > SpecialFunctionCategory) so I guess that's why it doesn't get numerically > evaluated. > The other version comes from an unexposed package > (FunctionalSpecialFunction), which I tried to package-call: > > riemannZeta(0.5+%i)$FSPECF(Complex(Float),Complex(Float)) > > which has no valid type. The command ')d op riemannZeta' instructs me what > the parameters of FSPECF would be, but I obviously didn't understand. > > Generically, how to parametrize a more complex domain? Where to read to > understand what is needed? > > Thank you! -- You received this message because you are subscribed to the Google Groups "FriCAS - computer algebra system" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. To view this discussion on the web visit https://groups.google.com/d/msgid/fricas-devel/221f0fb5-c98c-4789-9eee-42d5b810c103n%40googlegroups.com.
