Nick Barnes wrote:
On Thu, 25 Nov 2004 16:19:02 +0900, Rob <[EMAIL PROTECTED]> wrote:
time(minutes) * speed(MHz) * nproc / 1000 MHz
Looking at your examples, it seems you divide by 1e5, not by 1000.
Sorry, yes you're right.
In other words, buildworld is CPU bound and takes about 6e12 clock
cycles. Use -j<nproc>.
My main point is: when using "-j<nproc>", I am able to predict how long
the buildworld takes on a range of 'mainstream' systems like the ones I
have (pentium-II to pentium-IV and dual-pentium-III):
time(minutes) = 1e5 / ( speed(MHz) * nproc )
P-II 333 MHz : 300 min.
P-III 700 MHz : 142 min.
P-III 2x800 MHz : 62 min.
P-IV 2000 MHz : 50 min.
Within a few minutes, all these times are correct.
I still have to test my P-I/150 MHz also running 5.3, and verify
that buildworld will take approx. 670 min.
Rob.
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