On Wed, Jan 09, 2002 at 12:29:07AM +0100, aaron wrote: > Hm, ok the FAQ, but.... > recently - as seen on the well known mailing lists - there was a post > that 48bit addressing is now available. If I understood it correctly this > should give you (at least!) 2^48 = 256 TBytes. > > But I myself would like to know if this calculation is correct. > (or is it 2^48 blocks?)
Device size != Partition size != Filesystem size != File size 48-bit addressing is for addressing raw disk blocks on the device. Kris
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