Quoting Frank Leonhardt <fra...@fjl.co.uk>:
There are two common ways of defining a subnet mask - one is a
dotted quad (e.g. 255.255.255.0) and the other is with a slash and
the number of low-order bits - e.g. 192.168.1.0/8. Eight bits here
means you get 2^8 addresses (i.e. 256). Don't use the first and last
address in the range - the first is "complicated" (the network
address) and the last is for broadcast packets. This doesn't always
hold true but you're unlikely to come across exceptions.
This is the wrong way round. the number after the slash indicates the
number of bits in the network address - the high-order bits.
So, when you say you want to define a "network with mask 8" I don't
really know what you mean from your example. Do you mean a /8?
192.168.1.0/8 = range 192.168.1.1 192.168.1.254 with a subnet
mask of 255.255.255.0 (0xFFFFFF00)
Nope. 192.168.1.0/24 = 192.168.1.1-255 mask 255.255.255.0.
192.168.1.0/8 doesn't start where you think it does (and is arguably
the wrong way to specify that network) because all but the first 8
bits are masked out - it's 192.0.0.0 - 192.255.255.255.
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