On May 21, 2013, at 11:03 AM, Dmitry Sivachenko <trtrmi...@gmail.com> wrote: > Hello, > > Can you please explain me the meaning of RES column in top(1) output: > as far as I understand from man-page, it is resident portion of the process, > that is the amount of memory process takes from RAM.
Yes, that's the definition. > But I get: > > Mem: 55G Active, 23G Inact, 11G Wired, 3729M Cache, 9838M Buf, 97M Free > Swap: 49G Total, 14M Used, 49G Free > > > PID USERNAME THR PRI NICE SIZE RES STATE C TIME WCPU COMMAND > 93273 username 103 52 0 141G 115G uwait 22 25:37 19.82% XXX > > So I have a machine with 96GB of RAM, no swap is used and my process's > resident size is 115G (more than physical memory). Memory that has been allocated but not written to is associated with the process address space in terms of accounting, but does not actually consume physical memory. There's also copy-on-write memory (used for the program executable code itself, which is also typically also marked read-only), mmap()ing big sparse files or device special files like a video framebuffer (ie, an X11 server), and probably a few other things which can reserve lots of resident memory without actually consuming physical memory. Regards, -- -Chuck _______________________________________________ freebsd-questions@freebsd.org mailing list http://lists.freebsd.org/mailman/listinfo/freebsd-questions To unsubscribe, send any mail to "freebsd-questions-unsubscr...@freebsd.org"
