Chip Camden wrote:
On Jul 02 07:43, Aiza wrote:
I have a file containing this
drwxrwxr-x 14 89987 546 512 Jun 6 2009 7.2-RELEASE
drwxrwxr-x 14 89987 546 512 Mar 23 04:59 7.3-RELEASE
drwxrwxr-x 13 89987 546 512 Nov 23 2009 8.0-RELEASE
drwxrwxr-x 13 89987 546 512 Jul 1 04:56 8.1-RC2
I want to strip off everything to the left of the release
version so I end up with this.
7.2-RELEASE
7.3-RELEASE
8.0-RELEASE
8.1-RC2
How would I code to do this?
sed -e 's/.* //' < file
assuming there are no trailing spaces on each line.
Another alternative would be to create the list without all that detail:
ls -1
Wow do I feel stupid. You saw through my question to the underlying
problem causing the need to strip off that stuff. I just changed the
command from ls -l to ls -1 and got what I wanted in the first place.
Thanks
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