Chip Camden wrote:
On Jun 15 2010 17:06, Aiza wrote:
Aiza wrote:
I have a directory with files in it. The first 3 letters of the file
names is the group prefix. I'm trying to write a script to accept the 3
letter of the group followed by a * to mean its a prefix lookup. But
when I run it I get a message "NO match" that is not issued by the
script. Its like * is not allowed as input.
Looking for sample .sh code for handling this standard type of lookup or
some online tutorial that has sample code for bourne shell programming.
Here is the code
prefix_name1=$1
prefix_name2=`echo -n "${prefix_name1}" | sed 's/*.*$//'`
echo "prefix_name1 = ${prefix_name1}"
echo "prefix_name2 = ${prefix_name2}"
if [ ${prefix_name1} -nq ${prefix_name2} ]; then
echo "prefix_name2 = ${prefix_name2}"
fi
exerr "hard stop"
Here is the test and out put
# >admin cell*
admin: No match.
As others have mentioned, you need to quote or escape the * in the
command line:
admin "cell*"
You've also botched your regex (/*.*$/) -- it can't begin with a *. What
exactly
are you trying to match?
As shown in the posted test results you can see that the * is removed
from the input cell* and becomes cell and then cell* is compared to cell
to determine if a search by prefix command was entered on the script
command line. So the regex (/*.*$/) is working as coded as long as the
script command line is coded like this "cell*".
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