Aiza wrote:
CyberLeo Kitsana wrote:
On 06/05/2010 10:56 PM, Aiza wrote:
i) action="installworld"; $flag_count=$((flag_count+1));;
...
What is still wrong here
Bourne shell expands variables to their contents before evaluating.
Thus, the above assignment ends up expanding to '0=1'. Leave out the $
on the target variable, and it becomes 'flag_count=1', which is more
likely what you intended.
i) action="installworld"; flag_count=$((flag_count+1));;
But when tested it just put 1 into flag_count. it is not adding one to
the value all ready in flag_count.
Stilling missing the point here
I want to perform math here. if more than one flag is coded them I want
the count to increase by 1 for each flag on the command, not change the
contents of the count to 1.
Again take note this is .sh shell type.
shift; while getopts :ugr: arg; do case ${arg} in
u) action="freebsd-update";;
g) action="freebsd-upgrade";;
r) action="freebsd-rollback";;
?) exerr ${cmd_usage};;
esac; done; shift $(( ${OPTION} -1 ))
doing more testing if found that the above $(( ${OPTION} -1 ))
subtraction is not work either.
echo "OPTION = $OPTION" shows a value of 5, which is the 4 flags plus
the leading parm. I thought $(( ${OPTION} -1 )) meant it was subtracting
1 from the parm count which should make it 4 which is the number of
flags i passed.
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