You can loop through them using a shell script:
for i in `ls -lt | awk '{if ($8 == 2006) print $9}'`;do rm $i;done
-Derek
At 06:35 PM 3/5/2007, Gary Kline wrote:
Guys,
Having found $9 , how do I /bin/rm it (using system()--yes??)
in an awk one-liner?
I'm trying to remove from packages from long ago and find and
print them with
ls -lt | awk '{if ($8 == 2006) print $9}';
but what I want to remove the file pointed at by $9. I've tried
FILE=ARGV[9]; and using FILE within my system() call, but no-joy.
What's the magic here?
thanks in advance,
gary
--
Gary Kline [EMAIL PROTECTED] www.thought.org Public Service Unix
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