Dan, Bill, thank you, my bad for not reading the manpage thoroughly enough.
i was put off by reps being the first parameter, and interpreted [s] ( stepsize ) as being the separator string, and assumed there was no stepsize. sorry for the fuzz, but at least i upped my shellscripting abilities :-) regards, usleep On 3/29/06, Dan Nelson <[EMAIL PROTECTED]> wrote: > In the last episode (Mar 29), [EMAIL PROTECTED] said: > > > You > > > should be able to write a shell script > > > > as i stated in my message, i lack shell scripting experience. > > > > > that wraps jot and provides > > > its functionality in the same format as seq. > > > > yes, and to convert steps to reps you will need $reps = ($end - > > $start) / $steps, and then see the difference between your script and > > the output of an actual linux seq. > > > > for example: > > seq 1 2 60 gives 1..3..5..7..59 ( see also my php and csh > implementations ) > > > > a seq equivalent ( 3 par version ) would be: > > > > @ reps = ( $3 - $1 ) / $2 > > jot $reps $1 $3 > > > > which will give 1..3..5..7..9..12(!)..zzzz..60 > > > > so how would your implementation of seq by using jot look like? > > jot - $1 $3 $2 > > ( which in your case would be "jot - 1 60 2" ) > > -- > Dan Nelson > [EMAIL PROTECTED] > _______________________________________________ freebsd-questions@freebsd.org mailing list http://lists.freebsd.org/mailman/listinfo/freebsd-questions To unsubscribe, send any mail to "[EMAIL PROTECTED]"
